应用层读写nandflash示例-白红宇

应用层读写nandflash示例

阅读量：384 次

发布时间：2019-03-05

本文共 1024 字，大约阅读时间需要 3 分钟。

转载自：https://blog.csdn.net/caoshunxin01/article/details/79355410

为了不影响其他文件，最好再多分出一个分区，专门用于flash操作

include sys/ioctl.h

include stdio.h

include mtd/mtd-user.h

include sys/types.h

include sys/stat.h

include fcntl.h

include unistd.h

include string.h

include stdlib.h

#define N 32

#define OFS (0)

#define block_size (128*1024)

#define page_size (2*1024)

int main(int argc, const char *argv[])

{

int fd;

int i, j;

unsigned char oob_data[1024*2] =

{

0x53, 0x50, 0x4c, 0x20, 0, 0xff, 0, 0xff,

0x53, 0x50, 0x4c, 0x20, 0, 0xff, 0, 0xff,

0x53, 0x50, 0x4c, 0x20, 0, 0xff, 0, 0xff,

0x53, 0x50, 0x4c, 0x20, 0, 0xff, 0, 0xff

};

unsigned char oobbuf[N];

struct mtd_oob_buf oob = {0, N, oobbuf};

struct mtd_oob_buf my_oob = {0, N, oob_data};

fd = open("/dev/mtd3", O_RDWR);

if(fd < 0)

{

perror("fail to open\n");

exit(-1);

}

pwrite(fd, oob_data, 1024*2, 1024*4);//写时必须页对齐，一次写一页（2k）的整数位

memset(oob_data,0,32);

pread(fd, oob_data, 32, 1024*4);

for(i=0;i<32;i++)

{

if(i%8==0)

printf("\n");

printf("%2x ",oob_data[i]);

}

printf("\n");

return 0;

}

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